"पांचवीं घात वाले समीकरण": अवतरणों में अंतर
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→इतिहास: I corrected two things. Inadvertently I wrote the letter a instead of the letter d into the cube root formula. But now I wrote the letter d in it. Now it is correct. And inadvertently I wrote a komma into the numbers with the many decimals. But now I wrote a point instead of that. Now it is definitely totally correct. |
अनुनाद सिंह (वार्ता | योगदान) |
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पंक्ति 11:
== इतिहास ==
दूसरे, तीसरे और चौथे घात वाले समीकरणों को हमेशा मूलों का उपयोग करके हल किया जा सकता है।
: <math>cx^3 + dx^2 + ex + f = 0</math>
c, d, e, f के वास्तविक मान के लिये इसके मूल निम्नलिखित होंगे-
: <math>x = - \frac{d}{3c} - \frac{1}{3c}\sqrt[3]{d^3 - \frac{9}{2}cde + \frac{27}{2}c^2 f + \sqrt{\bigl(d^3 - \frac{9}{2}cde + \frac{27}{2}c^2 f\bigr)^2 - \bigl(d^2 - 3ce\bigr)^3}} -</math>
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